dewalt23293 Posted March 8, 2010 Report Share Posted March 8, 2010 i found a easy way to revive dead battery's, its quick and works 99.9% of the time, it has saved me a lot of money. ive been using my yellow tops for 5 years and they still work great someone told me i should make a video so i did and i posted it on youtube you will probably be skeptical until you try it watch----- Link to comment Share on other sites More sharing options...
morpheuzneo Posted March 10, 2010 Report Share Posted March 10, 2010 hey man.. great hacks! although it look a bit unsafe.. if you don't have to welder machine.. you can bring the battery to any workshop that have it.. and have them zapped your battery ? and.. you need to do the zapping to both (+) and (-) side? (reversing the polarity?) have you tried this on other device nicad batt? Link to comment Share on other sites More sharing options...
nightmaim Posted April 21, 2010 Report Share Posted April 21, 2010 As far as I know you don't need to reverse polarity in this technique, in fact is not really good. But the trick with the welder machine is true, Ni-CD batteries suffer from crystalline formations over the time which reduces the cell capacity (a.k.a. Memory Effect), the high current over the cells in a pulsed way can broke those crystals and revival the battery. If you don't have a welder machine you can do this with less than 5 bucks in your own house: For those that are not familiarized with diodes, the white strip is pointed to the RIGHT in the picture. Put the resistor underwater if you want, it gets real hot. Make pulses with the wires just like the guy in the video, just take care to not short the battery Link to comment Share on other sites More sharing options...
Bingobelle Posted April 21, 2010 Report Share Posted April 21, 2010 That was a nice tip. If you have 230 V between live and neutral, is the resistor supposed to be lika 11 to 12 ohms instead? Link to comment Share on other sites More sharing options...
nightmaim Posted April 21, 2010 Report Share Posted April 21, 2010 Due to the massive power dissipated in a 230V system, you'll need two resistors in a parallel configuration: 1/Req = 1/R1 + 1/R2 1/Req = ~0.037 + ~0.037 Req = 13.5 ohms Link to comment Share on other sites More sharing options...
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